(3x^2-80x+300)=0

Solution for (3x^2-80x+300)=0 equation:

(3x^2-80x+300)=0

We get rid of parentheses

3x^2-80x+300=0

a = 3; b = -80; c = +300;
Δ = b2-4ac
Δ = -802-4·3·300
Δ = 2800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2800}=\sqrt{400*7}=\sqrt{400}*\sqrt{7}=20\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-20\sqrt{7}}{2*3}=\frac{80-20\sqrt{7}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+20\sqrt{7}}{2*3}=\frac{80+20\sqrt{7}}{6}
$